Monday 15 September 2014

SOME IMP FACTS ABOUT MATH


                                                     ARYABHATTA

ARYABHATTA

INTERESTING FACTS

  • The word "MATHEMATICS" comes from the Greek μάθημα (máthema) which means "science, knowledge, or learning"; μαθηματικός (mathematikós) means "fond of learning".
  • The word "FRACTION" derives from the Latin " fractio - to break".
  • GEOMETRY(Ancient Greek: γεωμετρία; geo = earth, metria = measure) is a part of mathematics.
  • "ALGEBRA" comes Arabic word (al-jabr, literally, restoration)
  • There are just four numbers (after 1) which are the sums of the cubes of their digits:
153 = 1^3 + 5^3 + 3^3
370 = 3^3 + 7^3 + 0^3
371 = 3^3 + 7^3 + 1^3
407 = 4^3 + 0^3 + 7^3
  • 111,111,111 multiplied by 111,111,111 equals12,345,678,987,654,321.
  • Among all shapes with the same area circle has the shortest perimeter.
  • For every object there is a distance at which it looks its best.
  •  SEQUENCE OF NUMBERS WITHOUT 8

    12345679 x 09 = 111111111
    12345679 x 18 = 222222222
    12345679 x 27 = 333333333
    12345679 x 36 = 444444444
    12345679 x 45 = 555555555
    12345679 x 54 = 666666666
    12345679 x 63 = 777777777
    12345679 x 72 = 888888888
    12345679 x 81 = 999999999

    NUMERIC PALINDROMES WITH 1'S


    1 x 1 = 1
    11 x 11 = 121
    111 x 111 = 12321
    1111 x 1111 = 1234321
    11111 x 11111 = 123454321
    111111 x 111111 = 12345654321
    1111111 x 1111111 = 1234567654321
    11111111 x 11111111 = 123456787654321
    111111111 x 111111111 = 12345678987654321

    SEQUENTIAL 8'S WITH 9

    9 x 9 + 7 = 88
    98 x 9 + 6 = 888
    987 x 9 + 5 = 8888
    9876 x 9 + 4 = 88888
    98765 x 9 + 3 = 888888
    987654 x 9 + 2 = 8888888
    9876543 x 9 + 1 = 88888888
    98765432 x 9 + 0 = 888888888

    SEQUENTIAL 1'S WITH 9

    1 x 9 + 2 = 11
    12 x 9 + 3 = 111
    123 x 9 + 4 = 1111
    1234 x 9 + 5 = 11111
    12345 x 9 + 6 = 111111
    123456 x 9 + 7 = 1111111
    1234567 x 9 + 8 = 11111111
    12345678 x 9 + 9 = 111111111
    123456789 x 9 + 10 = 1111111111

    SEQUENTIAL INPUT OF NUMBERS WITH 8

    1 x 8 + 1 = 9
    12 x 8 + 2 = 98
    123 x 8 + 3 = 987
    1234 x 8 + 4 = 9876
    12345 x 8 + 5 = 98765
    123456 x 8 + 6 = 987654
    1234567 x 8 + 7 = 9876543
    12345678 x 8 + 8 = 98765432
    123456789 x 8 + 9 = 987654321


Thursday 4 September 2014

(MEDIAN, MEAN, MODE) FOR MBA 1st SEM

Measures of average in grouped and continuous data

The mean

We already know how to find the mean from a frequency table. Finding the mean for grouped or continuous data is very similar.
The grouped frequency table shows the number of CDs bought by a class of children in the past year.

 

Number of CDs Frequency (f)
0-410
5-912
10-146
15-192
>190
  • We know that 10 children have bought either 0, 1, 2, 3 or 4 CDs, but we do not know exactly how many each child bought.
  • If we assumed that each child bought 4 CDs, it is likely that our estimate of the mean would be too big.
  • If we assumed that each child bought 0 CDs, it is likely that our estimate would be too small.
  • It therefore seems sensible to use the mid-point of the group and assume that each child bought 2.
Finding the mid-points of the other groups, we get:

 

Number of CDsfMid-point, xfx
0-410220
5-912784
10-1461272
15-1921734
>190-0
The mean is 20 + 82 + 72 + 34 over 10 + 12 + 6 + 2 =  210 over 30 = 7
Remember: This is only an estimate of the mean.

The median

As explained previously, the median is the middle value when the values are arranged in order of size.
As the data has been grouped, we cannot find an exact value for the median, but we can find the class which contains the median.

 

Number of CDsFrequency (f)
0-410
5-912
10-146
15-192
>190
There are 30 children, so we are looking for the class which contains the (30 + 1) ÷ 2 = 1512th value. The median is therefore within the 5-9 class.

The mode

The mode is the most common value.
We cannot find an exact value for the mode, and therefore give the modal class. The modal class is 5-9.

Advantages and disadvantages of mean, median and mode

With three averages to choose from mean, median and mode – which should we use?
The following table shows the advantages and disadvantages of these different averages.

 

AverageAdvantagesDisadvantages
MeanAll the data is used to find the answerVery large or very small numbers can distort the answer
MedianVery big and very small values don't affect itTakes a long time to calculate for a very large set of data
Mode or modal classThe only average we can use when the data is not numerical
  1. There may be more than one mode
  2. There may be no mode at all if none of the data is the same
  3. It may not accurately represent the data
Example
This table shows the annual salary of people who work at a garden centre.

 

Annual salary (£)Number of people
0 - 9,99910
10,000 - 19,9999
20,000 - 29,9999
30,000 - 39,9991
40,000 - 49,9991
The modal class is £0 - £9,999.
Question
What is the disadvantage of using the modal class?
Answer
Even though the range £0 - £9,999 contains the most number of people, the next two ranges have comparable numbers and so is not representative of the data.
Question
What is the disadvantage of using the mean?
Almost everyone earns under £30,000. The mean would be distorted by the fact that two people earn much more than this.

Monday 1 September 2014

Standard deviation & Coefficient of variation (MBA 1st)

Z-4: Mean, Standard Deviation, And Coefficient Of Variation PDF Print
Written by Madelon F. Zady   
Don't be caught in your skivvies when you talk about CV's, or confuse STD's with SD's. Do you know what they mean when they talk about mean? These are the bread and butter statistical calculations. Make sure you're doing them right.

EdD Assistant Professor
Clinical Laboratory Science Program University of Louisville
Louisville, Kentucky
June 1999

Many of the terms covered in this lesson are also found in the lessons on Basic QC Practices, which appear on this website. It is highly recommended that you study these lessons online or in hard copy[1]. The importance of this current lesson, however, resides in the process. The lesson sets up a pattern to be followed in future lessons.

Mean or average

The simplest statistic is the mean or average. Years ago, when laboratories were beginning to assay controls, it was easy to calculate a mean and use that value as the "target" to be achieved. For example, given the following ten analyses of a control material - 90, 91, 89, 84, 88, 93, 80, 90, 85, 87 - the mean or Xbar is 877/10 or 87.7. [The term Xbar refers to a symbol having a line or bar over the X,mean, however, we will use the term instead of the symbol in the text of these lessons because it is easier to present.]
The mean value characterizes the "central tendency" or "location" of the data. Although the mean is the value most likely to be observed, many of the actual values are different than the mean. When assaying control materials, it is obvious that technologists will not achieve the mean value each and every time a control is analyzed. The values observed will show a dispersion or distribution about the mean, and this distribution needs to be characterized to set a range of acceptable control values.

Standard deviation

The dispersion of values about the mean is predictable and can be characterized mathematically through a series of manipulations, as illustrated below, where the individual x-values are shown in column A.
Column A Column B Column C
X value X value-Xbar (X-Xbar)2
90 90 - 87.7 = 2.30 (2.30)2 = 5.29
91 91 - 87.7 = 3.30 (3.30)2 = 10.89
89 89 - 87.7 = 1.30 (1.30)2 = 1.69
84 84 - 87.7 = -3.70 (-3.70)2 = 13.69
88 88 - 87.7 = 0.30 (0.30)2 = 0.09
93 93 - 87.7 = 5.30 (5.30)2 = 28.09
80 80 - 87.7 = -7.70 (-7.70)2 = 59.29
90 90 - 87.7 = 2.30 (2.30)2 = 5.29
85 85 - 87.7 = -2.70 (-2.70)2 = 7.29
87 87 - 87.7 = -0.70 (-0.70)2 = 0.49
X = 877 (X-Xbar) = 0 (X-Xbar)² = 132.10
  • The first mathematical manipulation is to sum (summation symbol) the individual points and calculate the mean or average, which is 877 divided by 10, or 87.7 in this example.
  • The second manipulation is to subtract the mean value from each control value, as shown in column B. This term, shown as X value - Xbar, is called the difference score. As can be seen here, individual difference scores can be positive or negative and the sum of the difference scores is always zero.
  • The third manipulation is to square the difference score to make all the terms positive, as shown in Column C.
  • Next the squared difference scores are summed.
  • Finally, the predictable dispersion or standard deviation (SD or s) can be calculated as follows:

= [132.10/(10-1)]1/2 = 3.83

Degrees of freedom

The "n-1" term in the above expression represents the degrees of freedom (df). Loosely interpreted, the term "degrees of freedom" indicates how much freedom or independence there is within a group of numbers. For example, if you were to sum four numbers to get a total, you have the freedom to select any numbers you like. However, if the sum of the four numbers is stipulated to be 92, the choice of the first 3 numbers is fairly free (as long as they are low numbers), but the last choice is restricted by the condition that the sum must equal 92. For example, if the first three numbers chosen at random are 28, 18, and 36, these numbers add up to 82, which is 10 short of the goal. For the last number there is no freedom of choice. The number 10 must be selected to make the sum come out to 92. Therefore, the degrees of freedom have been limited by 1 and only n-1 degrees of freedom remain. In the SD formula, the degrees of freedom are n minus 1 because the mean of the data has already been calculated (which imposes one condition or restriction on the data set).

Variance

Another statistical term that is related to the distribution is the variance, which is the standard deviation squared (variance = SD² ). The SD may be either positive or negative in value because it is calculated as a square root, which can be either positive or negative. By squaring the SD, the problem of signs is eliminated. One common application of the variance is its use in the F-test to compare the variance of two methods and determine whether there is a statistically significant difference in the imprecision between the methods.
In many applications, however, the SD is often preferred because it is expressed in the same concentration units as the data. Using the SD, it is possible to predict the range of control values that should be observed if the method remains stable. As discussed in an earlier lesson, laboratorians often use the SD to impose "gates" on the expected normal distribution of control values.

Normal or Gaussian distribution

Traditionally, after the discussion of the mean, standard deviation, degrees of freedom, and variance, the next step was to describe the normal distribution (a frequency polygon) in terms of the standard deviation "gates." The figure here is a representation of the frequency distribution of a large set of laboratory values obtained by measuring a single control material. This distribution shows the shape of a normal curve. Note that a "gate" consisting of ±1SD accounts for 68% of the distribution or 68% of the area under the curve, ±2SD accounts for 95% and ±3SD accounts for >99%. At ±2SD, 95% of the distribution is inside the "gates," 2.5% of the distribution is in the lower or left tail, and the same amount (2.5%) is present in the upper tail. Some authors call this polygon an error curve to illustrate that small errors from the mean occur more frequently than large ones. Other authors refer to this curve as a probability distribution.

Coefficient of variation

Another way to describe the variation of a test is calculate the coefficient of variation, or CV. The CV expresses the variation as a percentage of the mean, and is calculated as follows:
CV% = (SD/Xbar)100
In the laboratory, the CV is preferred when the SD increases in proportion to concentration. For example, the data from a replication experiment may show an SD of 4 units at a concentration of 100 units and an SD of 8 units at a concentration of 200 units. The CVs are 4.0% at both levels and the CV is more useful than the SD for describing method performance at concentrations in between. However, not all tests will demonstrate imprecision that is constant in terms of CV. For some tests, the SD may be constant over the analytical range.
The CV also provides a general "feeling" about the performance of a method. CVs of 5% or less generally give us a feeling of good method performance, whereas CVs of 10% and higher sound bad. However, you should look carefully at the mean value before judging a CV. At very low concentrations, the CV may be high and at high concentrations the CV may be low. For example, a bilirubin test with an SD of 0.1 mg/dL at a mean value of 0.5 mg/dL has a CV of 20%, whereas an SD of 1.0 mg/dL at a concentration of 20 mg/dL corresponds to a CV of 5.0%.

Alternate formulae

The lessons on Basic QC Practices cover these same terms (see QC - The data calculations), but use a different form of the equation for calculating cumulative or lot-to-date means and SDs. Guidelines in the literature recommend that cumulative means and SDs be used in calculating control limits [2-4], therefore it is important to be able to perform these calculations.
The cumulative mean can be expressed as Xbar = (summation symbolxi)t /nt, which appears similar to the prior mean term except for the "t" subscripts, which refer to data from different time periods. The idea is to add the summation symbolxi and n terms from groups of data in order to calculate the mean of the combined groups.
The cumulative or lot-to-date standard deviation can be expressed as follows:
This equation looks quite different from the prior equation in this lesson, but in reality, it is equivalent. The cumulative standard deviation formula is derived from an SD formula called the Raw Score Formula. Instead of first calculating the mean or Xbar, the Raw Score Formula calculates Xbar inside the square root sign.
Oftentimes in reading about statistics, an unfamiliar formula may be presented. You should realize that the mathematics in statistics is often redundant. Each procedure builds upon the previous procedure. Formulae that seem to be different are derived from mathematical manipulations of standard expressions with which you are often already acquainted.

References

  1. Westgard JO, Barry, PL, Quam EF. Basic QC practices: Training in statistical quality control for healthcare laboratories. Madison, WI: Westgard Quality Corporation, 1998.
  2. Westgard JO, Barry PL, Hunt MR, Groth, T. A multirule Shewhart chart for quality control in clinical chemistry. Clin Chem 1981;27:493-501.
  3. Westgard JO, Klee GG. Quality Management. Chapter 17 in Tietz Textbook of Clinical Chemistry, 3rd ed., Burtis and Ashwood, eds. Philadelphia, PA: Saunders, 1999.
  4. NCCLS C24-A2 document. Statistical quality control for quantitative measurements: Principles and definitions. National Committee for Clinical Laboratory Standards, Wayne PA, 1999.

Self-assessment exercises

  1. Manually calculate the mean, SD, and CV for the following data: 44, 47, 48, 43, 48.
  2. Use the SD Calculator to calculate the mean, SD, and CV for the following data: 203, 202, 204, 201, 197, 200, 198, 196, 206, 198, 196, 192, 205, 190, 207, 198, 201, 195, 209, 186.
  3. If the data above were for a cholesterol control material, calculate the control limits that would contain 95% of the expected values.
  4. If control limits (or SD "gates") were set as the mean +/- 2.5 SD, what percentage of the control values are expected to exceed these limits? [Hint: you need to find a table of areas under a normal curve.]
  5. Describe how to calculate cumulative control limits.
  6. (Optional) Show the equivalence of the regular SD formula and the Raw Score formula. [Hint: start with the regular formula, substitute a summation term for Xbar, multiply both sides by n/n, then rearrange.]

About the author: Madelon F. Zady

Madelon F. Zady is an Assistant Professor at the University of Louisville, School of Allied Health Sciences Clinical Laboratory Science program and has over 30 years experience in teaching. She holds BS, MAT and EdD degrees from the University of Louisville, has taken other advanced course work from the School of Medicine and School of Education, and also advanced courses in statistics. She is a registered MT(ASCP) and a credentialed CLS(NCA) and has worked part-time as a bench technologist for 14 years. She is a member of the: American Society for Clinical Laboratory Science, Kentucky State Society for Clinical Laboratory Science, American Educational Research Association, and the National Science Teachers Association. Her teaching areas are clinical chemistry and statistics. Her research areas are metacognition and learning theory.